A quadratic function has x intercepts 2 and -3 crosses the y axis at -1. What is the equation?
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Let $\displaystyle f(x)=ax^2+bx+c$ We have $\displaystyle f(2)=0\Rightarrow 4a+2b+c=0$ $\displaystyle f(-3)=0\Rightarrow 9a-3b+c=0$ $\displaystyle f(0)=-1\Rightarrow c=-1$ Now find a, b.
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