# Factor by grouping (don't understand it)

• Feb 8th 2009, 05:02 PM
mathhelp23
Factor by grouping (don't understand it)
How would I start this question. I don't know how to do it(Headbang)

FACTOR BY GROUPING:

xy+12+4x+3y
• Feb 8th 2009, 05:13 PM
Banned for attempted hacking
Quote:

Originally Posted by mathhelp23
How would I start this question. I don't know how to do it(Headbang)

FACTOR BY GROUPING:

xy+12+4x+3y

xy+12+4x+3y
collect like terms , thing that look the same

xy + 3y + 4x +12

y(x+3) + 4x +12
• Feb 9th 2009, 02:21 AM
GreenMile
xy+12+4x+3y

y(x+3) + 4x +12

y(x+3) + 4(x+3) => (y+4)(x+3)
• Feb 9th 2009, 03:03 AM
princess_21
Quote:

Originally Posted by mathhelp23
How would I start this question. I don't know how to do it(Headbang)

FACTOR BY GROUPING:

xy+12+4x+3y

$xy+12+4x+3y$

collect like terms
$(xy+4x)+(12+3y)$

you can see from here that there are like terms in the group, then factor.

$x(y+4)+3(y+4)$

the common factor is y+4, so

$(x+3)(y+4)$

remember the rules in factorization.