How would I start this question. I don't know how to do it(Headbang)

FACTOR BY GROUPING:

xy+12+4x+3y

Printable View

- Feb 8th 2009, 04:02 PMmathhelp23Factor by grouping (don't understand it)
How would I start this question. I don't know how to do it(Headbang)

FACTOR BY GROUPING:

xy+12+4x+3y - Feb 8th 2009, 04:13 PMBanned for attempted hacking
- Feb 9th 2009, 01:21 AMGreenMile
xy+12+4x+3y

y(x+3) + 4x +12

y(x+3) + 4(x+3) => (y+4)(x+3) - Feb 9th 2009, 02:03 AMprincess_21
$\displaystyle xy+12+4x+3y$

collect like terms

$\displaystyle (xy+4x)+(12+3y)$

you can see from here that there are like terms in the group, then factor.

$\displaystyle x(y+4)+3(y+4)$

the common factor is y+4, so

$\displaystyle (x+3)(y+4)$

remember the rules in factorization.