the range is given in this way:

y1=-1

y(n+1)=1/3y(n)+3

Find a f function y(n)=f(n)

thanks

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- February 8th 2009, 12:39 PMblerttarecurrence
the range is given in this way:

y1=-1

y(n+1)=1/3y(n)+3

Find a f function y(n)=f(n)

thanks - February 8th 2009, 03:46 PMJester