Is this the correct expansion $\displaystyle (2 - x)^{-1} = \frac{1}{2} + x + \frac{x^2}{4}$

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- Feb 8th 2009, 10:26 AMBeardBinomial expansion
Is this the correct expansion $\displaystyle (2 - x)^{-1} = \frac{1}{2} + x + \frac{x^2}{4}$

- Feb 8th 2009, 10:46 AMred_dog
No.

$\displaystyle (2-x)^{-1}=\frac{1}{2-x}$ - Feb 8th 2009, 10:51 AMBeard
I mean when you expand it up to x^2 using binomial expansion