
Find 'i' where i^2 = 1
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The answer should be 7/5  17i/10 but somehow I couldn't figure it out.
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The answer should be 2 3i/2 but I always get 2 +3i/2 for my answer. Help please?
i is an imaginary number. That is i^2 = 1

when you say find 'i' do you mean make i the subject? because the answer is 7/5  17i/10, which has 'i' in it .

$\displaystyle \frac {83i46i}{2+4i}=\frac {49i}{2+4i}=a+bi\rightarrow 49i=(2+4i)(a+bi)=2a+4ai+2bi4b=$$\displaystyle 2a4b+(4a+2b)i$ So $\displaystyle 4=2a4b$ and $\displaystyle 9=4a+2b$. Can you continue from here?