Thread: Natural logarithm

Solve for x.

a ln(bx+c)=d

Originally Posted by krakra

Solve for x.

a ln(bx+c)=d

$\displaystyle ln(bx+c) = d/a$

$\displaystyle bx+c = e^{d/a}$

$\displaystyle bx = e^{d/a}-c$

$\displaystyle x = \frac{e^{d/a}-c}{b}$