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Solve for x. a ln(bx+c)=d

Quote: Originally Posted by krakra Solve for x. a ln(bx+c)=d $\displaystyle ln(bx+c) = d/a$ $\displaystyle bx+c = e^{d/a}$ $\displaystyle bx = e^{d/a}-c$ $\displaystyle x = \frac{e^{d/a}-c}{b}$