Natural logarithm

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February 7th 2009, 07:12 PM
krakra

Natural logarithm

Solve for x.

a ln(bx+c)=d
February 7th 2009, 07:38 PM
Rapha

Quote:

Originally Posted by krakra

Solve for x.

a ln(bx+c)=d

$ln(bx+c) = d/a$

$bx+c = e^{d/a}$

$bx = e^{d/a}-c$

$x = \frac{e^{d/a}-c}{b}$

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