# Math Help - How do you solve the problem: 0=3^2x-5X+2

1. ## How do you solve the problem: 0=3^2x-5X+2

I got the answer of
X=1, X=2/3

but the answer in the book is -1/3,2

This is how I did it:
0=3^2x-5X+2
0=3^2x-3X-2X+2
0=3X(X -1) + 2 (X-1)
0= (X-1)(3X+2)
0= 1, -2/3

2. Originally Posted by positiveion
I got the answer of
X=1, X=2/3

but the answer in the book is -1/3,2

This is how I did it:
0=3^2x-5X+2
0=3^2x-3X-2X+2
0=3X(X -1) + 2 (X-1)
0= (X-1)(3X+2)
0= 1, -2/3
confirm the equation ... is it

$3x^2 - 5x + 2 = 0$

?

3. yes

4. $0= 3x^2-3X-2X+2$

$0= 3X(X -1)-2 (X-1)$

$0= (X-1) ( 3X-2)$

EDIT: Watch Princess's reply

5. Originally Posted by positiveion
I got the answer of
X=1, X=2/3

but the answer in the book is -1/3,2

This is how I did it:
0=3^2x-5X+2
0=3^2x-3X-2X+2
0=3X(X -1) + 2 (X-1)
0= (X-1)(3X+2)
0= 1, -2/3

if the equation is

$3x^2-5x+2$

but you said that the answer in the book is $-\frac{1}{3}, 2$
$3x^2-5x-2$