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Math Help - How do you solve the problem: 0=3^2x-5X+2

  1. #1
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    How do you solve the problem: 0=3^2x-5X+2

    I got the answer of
    X=1, X=2/3

    but the answer in the book is -1/3,2

    This is how I did it:
    0=3^2x-5X+2
    0=3^2x-3X-2X+2
    0=3X(X -1) + 2 (X-1)
    0= (X-1)(3X+2)
    0= 1, -2/3
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  2. #2
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    Quote Originally Posted by positiveion View Post
    I got the answer of
    X=1, X=2/3

    but the answer in the book is -1/3,2

    This is how I did it:
    0=3^2x-5X+2
    0=3^2x-3X-2X+2
    0=3X(X -1) + 2 (X-1)
    0= (X-1)(3X+2)
    0= 1, -2/3
    confirm the equation ... is it

    3x^2 - 5x + 2 = 0

    ?
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  3. #3
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    yes
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  4. #4
    Like a stone-audioslave ADARSH's Avatar
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    0= 3x^2-3X-2X+2

    0= 3X(X -1)-2 (X-1)

    0= (X-1) ( 3X-2)

    EDIT: Watch Princess's reply
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  5. #5
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    Quote Originally Posted by positiveion View Post
    I got the answer of
    X=1, X=2/3

    but the answer in the book is -1/3,2

    This is how I did it:
    0=3^2x-5X+2
    0=3^2x-3X-2X+2
    0=3X(X -1) + 2 (X-1)
    0= (X-1)(3X+2)
    0= 1, -2/3

    if the equation is

    3x^2-5x+2

    then your answer is correct

    but you said that the answer in the book is -\frac{1}{3}, 2

    then the equation must be,

    3x^2-5x-2

    is it the equation in your book?
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