Thread: How do you solve the problem: 0=3^2x-5X+2

I got the answer of
X=1, X=2/3

but the answer in the book is -1/3,2

This is how I did it:
0=3^2x-5X+2
0=3^2x-3X-2X+2
0=3X(X -1) + 2 (X-1)
0= (X-1)(3X+2)
0= 1, -2/3

Originally Posted by positiveion

I got the answer of
X=1, X=2/3

but the answer in the book is -1/3,2

This is how I did it:
0=3^2x-5X+2
0=3^2x-3X-2X+2
0=3X(X -1) + 2 (X-1)
0= (X-1)(3X+2)
0= 1, -2/3

confirm the equation ... is it



?

yes

EDIT: Watch Princess's reply

Originally Posted by positiveion

I got the answer of
X=1, X=2/3

but the answer in the book is -1/3,2

This is how I did it:
0=3^2x-5X+2
0=3^2x-3X-2X+2
0=3X(X -1) + 2 (X-1)
0= (X-1)(3X+2)
0= 1, -2/3

if the equation is



then your answer is correct

but you said that the answer in the book is

then the equation must be,



is it the equation in your book?