I got the answer of X=1, X=2/3 but the answer in the book is -1/3,2 This is how I did it: 0=3^2x-5X+2 0=3^2x-3X-2X+2 0=3X(X -1) + 2 (X-1) 0= (X-1)(3X+2) 0= 1, -2/3
Follow Math Help Forum on Facebook and Google+
Originally Posted by positiveion I got the answer of X=1, X=2/3 but the answer in the book is -1/3,2 This is how I did it: 0=3^2x-5X+2 0=3^2x-3X-2X+2 0=3X(X -1) + 2 (X-1) 0= (X-1)(3X+2) 0= 1, -2/3 confirm the equation ... is it $\displaystyle 3x^2 - 5x + 2 = 0 $ ?
yes
$\displaystyle 0= 3x^2-3X-2X+2$ $\displaystyle 0= 3X(X -1)-2 (X-1)$ $\displaystyle 0= (X-1) ( 3X-2)$ EDIT: Watch Princess's reply
Originally Posted by positiveion I got the answer of X=1, X=2/3 but the answer in the book is -1/3,2 This is how I did it: 0=3^2x-5X+2 0=3^2x-3X-2X+2 0=3X(X -1) + 2 (X-1) 0= (X-1)(3X+2) 0= 1, -2/3 if the equation is $\displaystyle 3x^2-5x+2$ then your answer is correct but you said that the answer in the book is $\displaystyle -\frac{1}{3}, 2$ then the equation must be, $\displaystyle 3x^2-5x-2$ is it the equation in your book?
View Tag Cloud