I am very stuck as to how to attempt this question, would really appreciate some help as lecturer was not clear
xn+6 - 3xn+4 + 3xn+2 - xn = 0
given initial condition
X0=X2=X4=0, X1=2, X3=12, X5=30
Please help me, would be so grateful
I am very stuck as to how to attempt this question, would really appreciate some help as lecturer was not clear
xn+6 - 3xn+4 + 3xn+2 - xn = 0
given initial condition
X0=X2=X4=0, X1=2, X3=12, X5=30
Please help me, would be so grateful
Hello, manalive04!
I have an "eyeball" solution . . .
$\displaystyle x_{n+6} - 3x_{n+4} + 3x_{n+2} - x_n \;=\;0$
Given initial conditions:
. . $\displaystyle \begin{array}{c}x_0\:=\:0\\
x_1 \:=\:2 \\ x_2 \:=\:0 \\ x_3 \:=\:12 \\ x_4 \:=\:0 \\ x_5 \:=\:30 \\
\vdots \end{array}$
We have: .$\displaystyle \begin{array}{ccc}x_0 &=&0 \\ x_1 &=&1\!\cdot\!2 \\ x_2 &=& 0 \\ x_3 &=&3\!\cdot\!4 \\ x_4&=& 0 \\ x_5 &=& 5\!\cdot\!6 \\ \vdots & &\vdots \end{array}$
We see that: .$\displaystyle x_n \;=\;\begin{Bmatrix}0 & \text{for even }n \\ n(n+1) & \text{ for odd }n \end{Bmatrix}$
Therefore, the general term is: .$\displaystyle x_n \;=\;\frac{1 - (-1)^n}{2}\,n(n+1)$