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Math Help - Solving a System?

  1. #1
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    Solving a System?

    Hey Guys!
    This is my last question of the Unit that I am planning to send in tomorrow morning.

    My text does not provide me with enough examples or information to help me solve this question so I'm looking for some answers please!

    Solve the following system:
    2^(x+3y) =128 and 2^(3x-7)=2



    Thank You for any help anyone can provide to me!
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  2. #2
    MHF Contributor red_dog's Avatar
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    \left\{\begin{array}{ll}2^{x+3y}=2^7\\2^{3x-7}=2^1\end{array}\right.\Rightarrow\left\{\begin{a  rray}{ll}x+3y=7\\3x-7=1\end{array}\right.

    Now you have yo solve the last system.
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  3. #3
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    Thanks for the reply

    That is actually as far as I got....
    I don't understand what I have to do next or how to even go about this...
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  4. #4
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    Quote Originally Posted by red_dog View Post
    \left\{\begin{array}{ll}2^{x+3y}=2^7\\2^{3x-7}=2^1\end{array}\right.\Rightarrow\left\{\begin{a  rray}{ll}x+3y=7\\3x-7=1\end{array}\right.

    Now you have yo solve the last system.
    Quote Originally Posted by lil_cookie View Post
    Thanks for the reply

    That is actually as far as I got....
    I don't understand what I have to do next or how to even go about this...
    From red-dog's work, solve the second for x

    x = \frac{8}{3}

    then substitute into the first to get y.
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  5. #5
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    Oh I got it

    Thank you 2
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