Thread: I've tried and I've tried, but...

1. I've tried and I've tried, but...

I can't do my homework. Could you please help me?

I need to solve this one:

5x x 5^2x+1 = 40

and this one, too:

4x^6 - 48 = 4

2. Originally Posted by Liza88
I can't do my homework. Could you please help me?

I need to solve this one:

5x x 5^2x+1 = 40

and this one, too:

4x^6 - 48 = 4
Your first equation is unintelligible. Do you mean $\displaystyle (5x) 5^{2x + 1} = 40$ ? You will need to post it much more clearly.

For the second, do you mean $\displaystyle 4 x^6 - 48 = 4$ ? In which case yu have $\displaystyle 4 x^6 = 52 \Rightarrow x^6 = \frac{52}{4} = 13$. Now take the sixth root of each side.

3. The first one is supposed to be:

5X multiply 5power2x+1 = 40

and the second one:

5powerx multiply 5power2x+1 = 40

I can't count neither of those

4. Originally Posted by Liza88
The first one is supposed to be:

5X multiply 5power2x+1 = 40

and the second one:

5powerx multiply 5power2x+1 = 40

I can't count neither of those
I don't understand your first question.

If I read your second question correctly ... (?):

\displaystyle \begin{aligned}5^x\cdot 5^{2x+1} = 40\\ 5 \cdot 5^y \cdot 5^{2x} = 40\\ 5^{3x} =8 = 2^3\\ 5^x= 2\\ x=\log_5(2)\end{aligned}

5. Thank you!

The first one is:

5X * 5^2X+1 = 40

I hope that is understandable, I don't know how to write it any other way.

6. Originally Posted by Liza88
Thank you!

The first one is:

5X * 5^2X+1 = 40

I hope that is understandable, I don't know how to write it any other way.
Do you mean:

(5x)*(5^(2x)) +1 = 40 ........... or

(5x)*(5^(2x+1)) = 40 ........... or

(5x)*(5^2)(x+1) = 40 ........... or

(5x)*(5^2(x+1)) = 40 ........... ???

7. Thank you very much, your answer was fine!