Solve the following system:

$\displaystyle 3(x + \frac {1}{x}) = 4(y + \frac {1}{y}) = 5(z + \frac {1}{z});\ xy + yz + zx = 1$

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- Feb 4th 2009, 06:26 PMalexmahoneSolve for x, y and z
Solve the following system:

$\displaystyle 3(x + \frac {1}{x}) = 4(y + \frac {1}{y}) = 5(z + \frac {1}{z});\ xy + yz + zx = 1$