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Math Help - Question..

  1. #1
    Newbie
    Joined
    Feb 2009
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    Question..

    Hi,

    I have Q I need some help with. Help is always much appreciated!

    I need to write the following expression as a single logarithm:

    3loga - logb - (1/2)logc

    This is what I have so far:

    3log(a/b) - (1/2)logc

    then:

    log(a/b)^3
    --------------
    (1/2)c

    I'm not thinking this is correct though. Any thoughts?

    Thanks,

    Jim.
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  2. #2
    Senior Member mollymcf2009's Avatar
    Joined
    Jan 2009
    From
    Charleston, SC
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    Quote Originally Posted by jimstewart_NC View Post
    Hi,

    I have Q I need some help with. Help is always much appreciated!

    I need to write the following expression as a single logarithm:

    3loga - logb - (1/2)logc

    This is what I have so far:

    3log(a/b) - (1/2)logc

    then:

    log(a/b)^3
    --------------
    (1/2)c

    I'm not thinking this is correct though. Any thoughts?

    Thanks,

    Jim.
    Hi Jim,
    Found ya again huh?

    Actually first I would get rid of your multipliers by moving them inside of your arguement. That's the beauty of logs

    So you have,

    3log(a) - log(b) - \frac{1}{2}log(c)

    = log(a)^3 - log(b) - log (c)^{\frac{1}{2}}

    Then combine them. Remember that c^{\frac{1}{2}} = \sqrt{c}

    See if you can finish it up! Good luck!!
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