1. ## Question..

Hi,

I have Q I need some help with. Help is always much appreciated!

I need to write the following expression as a single logarithm:

3loga - logb - (1/2)logc

This is what I have so far:

3log(a/b) - (1/2)logc

then:

log(a/b)^3
--------------
(1/2)c

I'm not thinking this is correct though. Any thoughts?

Thanks,

Jim.

2. Originally Posted by jimstewart_NC
Hi,

I have Q I need some help with. Help is always much appreciated!

I need to write the following expression as a single logarithm:

3loga - logb - (1/2)logc

This is what I have so far:

3log(a/b) - (1/2)logc

then:

log(a/b)^3
--------------
(1/2)c

I'm not thinking this is correct though. Any thoughts?

Thanks,

Jim.
Hi Jim,
Found ya again huh?

Actually first I would get rid of your multipliers by moving them inside of your arguement. That's the beauty of logs

So you have,

$3log(a) - log(b) - \frac{1}{2}log(c)$

$= log(a)^3 - log(b) - log (c)^{\frac{1}{2}}$

Then combine them. Remember that $c^{\frac{1}{2}} = \sqrt{c}$

See if you can finish it up! Good luck!!