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Math Help - distance problem

  1. #1
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    Question distance problem

    I have having problem solving this.
    One train leaves a station heading due west. Two hours later a second train leaves the same station heading due east. The second train is traveling 15 mi/hr faster than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate at which east train is traveling.
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  2. #2
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    Quote Originally Posted by barefoot12 View Post
    I have having problem solving this.
    One train leaves a station heading due west. Two hours later a second train leaves the same station heading due east. The second train is traveling 15 mi/hr faster than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate at which east train is traveling.

    1st=x

    2nd= 15+x

     total in 6 hrs= 6(x+15+x)=580

    12x+90=580

    12x=490

    x=40.83 mi/hr

    15+x= 15+40.83

    2nd train =55.83mi/hr going east
    Last edited by princess_21; February 6th 2009 at 03:18 AM.
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  3. #3
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    Quote Originally Posted by barefoot12 View Post
    One train leaves a station heading due west. Two hours later a second train leaves the same station heading due east. The second train is traveling 15 mi/hr faster than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate at which east train is traveling.
    Try setting up the information explicitly in terms of the "d = rt" equation.

    . . . . .first train:
    . . . . .rate: r
    . . . . .time: 2 + 6 = 8
    . . . . .distance: 8r

    . . . . .second train:
    . . . . .rate: r + 15
    . . . . .time: 6
    . . . . .distance: 6(r + 15) = 6r + 90

    They are headed in opposite directions, so the distance between them is the sum of their two distances:

    . . . . .total distance:
    . . . . .8r + 6r + 90 = 580

    Then:

    . . . . .14r = 490

    Divide through by 14 to find the rate of the first train. Back-solve to find the rate of the second train.

    Have fun!
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