Hello, Jim!
This is what I have so far:
Am I on the right track here?
Then we have: .
. . . . . . . . . . . . . . . . . Do you see why?
. . . . . . . . . . . . . .
Hi,
I'm having difficulty beginning to solve the following log problem:
6^(2log6x + log6x) = 125 (Where the the two 6's are the base of the logs)
Any help is much appreciated.
This is what I have so far:
6^(log6x^2 + log6x) = 125
6^(log6 (x^2) (x) ) = 125
Am I on the right track here? Do I have to make the 6 and 125 the same base to solve?
Thanks,
Jim.