Hi,

I'm having difficulty beginning to solve the following log problem:

(Where the the two 6's are the base of the logs)

6^(2log6x + log6x) = 125

Any help is much appreciated.

This is what I have so far:

6^(log6x^2 + log6x) = 125

6^(log6 (x^2) (x) ) = 125

Am I on the right track here? Do I have to make the 6 and 125 the same base to solve?

Thanks,

Jim.