4(h+3) im not sure i think the answer may be h+7 but i don't think it is. can anyone help please.
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Originally Posted by andyboy179 4(h+3) im not sure i think the answer may be h+7 but i don't think it is. can anyone help please. just distribute this. you will get: $\displaystyle 4(h+3)=4h+12$
Originally Posted by GaloisTheory1 just distribute this. you will get: $\displaystyle 4(h+3)=4h+12$ could u please tell me how u come to that answer like explain it.
Originally Posted by andyboy179 4(h+3) im not sure i think the answer may be h+7 but i don't think it is. can anyone help please. there is no way to get the "answer" , h + 7 , from the expression 4(h + 3). you could distribute the 4, like so ... $\displaystyle 4(h + 3) = 4 \cdot h + 4 \cdot 3 = 4h + 12$ ... which is about all that can be done.
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