# how would i simplify this

• Feb 3rd 2009, 06:52 AM
andyboy179
how would i simplify this
4(h+3) im not sure i think the answer may be h+7 but i don't think it is. can anyone help please.
• Feb 3rd 2009, 06:57 AM
GaloisTheory1
Quote:

Originally Posted by andyboy179
4(h+3) im not sure i think the answer may be h+7 but i don't think it is. can anyone help please.

just distribute this.

you will get:

$\displaystyle 4(h+3)=4h+12$
• Feb 3rd 2009, 06:59 AM
andyboy179
Quote:

Originally Posted by GaloisTheory1
just distribute this.

you will get:

$\displaystyle 4(h+3)=4h+12$

could u please tell me how u come to that answer like explain it.
• Feb 3rd 2009, 07:01 AM
skeeter
Quote:

Originally Posted by andyboy179
4(h+3) im not sure i think the answer may be h+7 but i don't think it is. can anyone help please.

there is no way to get the "answer" , h + 7 , from the expression
4(h + 3).

you could distribute the 4, like so ...

$\displaystyle 4(h + 3) = 4 \cdot h + 4 \cdot 3 = 4h + 12$

... which is about all that can be done.