Please help me to solve these four:
X^2 = 9/16
and
X/6 = 15 + x
and
X^2 - X - 6 = 0
and
2x^2 - 3x = 0
Thank you very much!
$\displaystyle (\sqrt{x})^2=\sqrt{\frac{9}{16}}$X^2 = 9/16
$\displaystyle x=\frac{3}{4}$$\displaystyle x= -\frac{3}{4}$ as corrected by earboth$\displaystyle \frac{x}{6}*\frac{6}{6}= 6(15 + x)$
$\displaystyle X/6 = 15 + x$
$\displaystyle x= 90 +6x$
$\displaystyle x-6x = 90$
$\displaystyle -5x = 90$
$\displaystyle x= -18$
$\displaystyle (x+2)(x-3)=0$X^2 - X - 6 = 0
$\displaystyle x+2=0 | x-3=0$
$\displaystyle x=-2 |x=3$
2x^2 - 3x = 0
try doing the last one.