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Math Help - Help needed.

  1. #1
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    Help needed.

    Please help me to solve these four:

    X^2 = 9/16

    and

    X/6 = 15 + x

    and

    X^2 - X - 6 = 0

    and

    2x^2 - 3x = 0


    Thank you very much!
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  2. #2
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    Quote Originally Posted by Shandy View Post
    Please help me to solve these four:
    Thank you very much!
    X^2 = 9/16
    (\sqrt{x})^2=\sqrt{\frac{9}{16}}

    x=\frac{3}{4}
     x= -\frac{3}{4} as corrected by earboth

    X/6 = 15 + x
    \frac{x}{6}*\frac{6}{6}= 6(15 + x)

    x= 90 +6x

    x-6x = 90

    -5x = 90

    x= -18

    X^2 - X - 6 = 0
    (x+2)(x-3)=0

    x+2=0 | x-3=0

    x=-2 |x=3


    2x^2 - 3x = 0

    try doing the last one.
    Last edited by princess_21; February 3rd 2009 at 01:46 AM.
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  3. #3
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    Quote Originally Posted by Shandy View Post
    Please help me to solve these four:

    X^2 = 9/16

    ...
    Keep in mind that \sqrt{x^2} = |x|

    Calculate the square root on both sides of your equation:

    x^2=\dfrac9{16}~\implies~|x|=\dfrac34~\implies~x=-\dfrac34~\vee~x=\dfrac34
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  4. #4
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    forgot that part. thanks
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