Please help me to solve these equations:

2 8

X = -

15

and:

2

X x 3x = -X + 4

Thank you !

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- Feb 2nd 2009, 10:53 PMShandySolve two algebra problems
Please help me to solve these equations:

2 8

X = -

15

and:

2

X x 3x = -X + 4

Thank you ! - Feb 2nd 2009, 11:00 PMGrandadExplain, please
- Feb 2nd 2009, 11:01 PMJhevon
- Feb 3rd 2009, 01:29 AMGrandadAlgebra
Hello Shandy

I'm just guessing that your first equation might be

If it is, the answers are

So get your calculator working! Divide 8 by 15. Then find the square root. Then put a sign in front, because there will be two answers.

The second one, I think, might be:

If so, then you solve it like this:

How am I doing? Did I guess right?

Grandad - Feb 3rd 2009, 05:30 AMstapel
Looking at your post inside "Quote" tags, some of the original formatting is displayed while in message-entry mode. Assuming you are using "X" and "x" to actually be the same variable, your equations appear to be:

. . . . .x^2 = 8/15

. . . . .(x)(3x) = -x^2 + 4

If so, then you can solve the first equation by**taking the square root**of each side of the equation, remembering the "plus-minus" on the right-hand side. You'll probably need to "**rationalize the denominator**" to get the answer in the "right" format.

For the second one, simplify the left-hand side to get 3x^2. Get the variable term together, and then divide 4x^2 = 4 on both sides by 4. Then you can solve by taking the square root of either side.

Have fun! :D