Results 1 to 8 of 8

Math Help - Factoring involving Fractional exponents

  1. #1
    Newbie
    Joined
    Feb 2009
    Posts
    6

    Factoring involving Fractional exponents

    Hey guys, i was wondering if someone cud help me out with this problem!
    Thanks in Advance !

    Factor and simplify

    (x+4)^1/5 - (x+4)^6/5

    need some help asap!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Sep 2008
    From
    West Malaysia
    Posts
    1,261

    Re :

     (x+4)^{\frac{1}{5}}-(x+4)^{\frac{6}{5}}

     <br />
=(x+4)^{\frac{1}{5}}(1-(x+4)^6)<br />
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Feb 2009
    Posts
    6
    thanks for the reply and the answer... but i didnt understand how you did that, if you can just explain a little , i would really appreciate it , thank you very much
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Joined
    Sep 2008
    From
    West Malaysia
    Posts
    1,261
    Take out the common factor which is (x+4)^{\frac{1}{5}} .

    so the first part of the equation reduces to 1 and the second part has a power of 6 ( Note that \frac{1}{5}\times6=\frac{6}{5})
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Feb 2009
    Posts
    6
    Thank you!
    Follow Math Help Forum on Facebook and Google+

  6. #6
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by mathaddict View Post
     (x+4)^{\frac{1}{5}}-(x+4)^{\frac{6}{5}}

     <br />
=(x+4)^{\frac{1}{5}}(1-(x+4)^{\color{red}6})<br />
    actually, the powers must ADD to give the original. so that 6 should be 1, since 1 + 1/5 gives the original 6/5 for the power of the second term.
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Newbie
    Joined
    Feb 2009
    Posts
    6
    Alright.. Thank you, that will be noted
    Follow Math Help Forum on Facebook and Google+

  8. #8
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by xxabbasxx View Post
    Alright.. Thank you, that will be noted
    yes, it should be noted already that x^a \cdot x^b = x^{a + b}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 4
    Last Post: January 23rd 2011, 11:54 AM
  2. negative fractional exponents
    Posted in the Algebra Forum
    Replies: 4
    Last Post: June 6th 2010, 02:24 PM
  3. Factoring involving Fractional exponents
    Posted in the Algebra Forum
    Replies: 2
    Last Post: February 3rd 2009, 08:20 AM
  4. Replies: 3
    Last Post: July 14th 2008, 09:58 PM
  5. [SOLVED] Fractional Exponents
    Posted in the Algebra Forum
    Replies: 1
    Last Post: December 3rd 2006, 08:30 PM

Search Tags


/mathhelpforum @mathhelpforum