I have to prove the distributive law (x+y)z = xz + yz using induction. I have fixed x,y in the Natural Numbers. Im working on the base case now. So...(x+y)0 , but how do I show that it equals x0 + y0??
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Originally Posted by jzellt I have to prove the distributive law (x+y)z = xz + yz using induction. I have fixed x,y in the Natural Numbers. Im working on the base case now. So...(x+y)0 , but how do I show that it equals x0 + y0?? Can you put the exact problem on here word for word? (that will tell us more information on what you can work with.)
Originally Posted by jzellt I have to prove the distributive law (x+y)z = xz + yz using induction. I have fixed x,y in the Natural Numbers. Im working on the base case now. So...(x+y)0 , but how do I show that it equals x0 + y0?? Because 0 times anything is 0.
what Mush said. you can write something like (x + y)*0 = 0 = 0 + 0 = x*0 + y*0
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