How do you solve the following system using elimination!
2x-3y=61
2x+y=-7
Good day to you
E is supposed to mean equation
(E1) 2x-3y=61
(E2) 2x+y=-7
Comparing E1 with E2 you see they both have '+2x' in it. Thus we calculate (E1) - (E2) and you get
2x-3y - [2x+y]=61 - [-7]
More calculating
2x - 3y - 2x -y = 61 + 7
2x - 2x -3y - y = 68
-3y - y = 68
-4y = 68
y = - 17
how to get x? Use y = - 17 in (E1) for example, then
(E1) 2x-3*(-17)=61
2x + 51 = 61
2x = 10
x = 5
Okay?
Cheers,
Rapha