Originally Posted by

**Grandad** Hello again IndoorKidI finally got round to looking at this one. I'm not sure that I'm understanding the question here, because I don't think it's possible that N can be a multiple of 9. Why do I say that? Well, it's all to do with the sum of the digits again. If by (abc)(bca)(cab) we mean a number like 125,251,512, where a = 1, b = 2 and c = 5, then it's definitely not possible, because these digits always add up to 3(a + b + c) which is a multiple of 3. Therefore the number itself is a multiple of 3. So if we add one to it, it can't possibly be a multiple of 3 (or 9), can it?

Grandad