$\displaystyle \sqrt[4]{x^6}$ Attempt $\displaystyle x^1\sqrt[4]{x^2}$ OR $\displaystyle \sqrt[2]{x^3}$ Which of the following is correct and why?
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Originally Posted by mj.alawami $\displaystyle \sqrt[4]{x^6}$ Attempt $\displaystyle x^1\sqrt[4]{x^2}$ OR $\displaystyle \sqrt[2]{x^3}$ Which of the following is correct and why? Both! $\displaystyle \sqrt[4]{x^6} = \left(x^6\right)^{\frac14} = x^{\frac64} = x^{1+\frac12} = x \cdot \sqrt{x} $ $\displaystyle \sqrt[4]{x^6} = \left(x^6\right)^{\frac14} = x^{\frac64} = x^{\frac32} = \sqrt{x^3} $
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