[SOLVED] Simplyfying

Printable View

Feb 1st 2009, 03:25 AM
mj.alawami

[SOLVED] Simplyfying

$\sqrt[4]{x^6}$

Attempt
$x^1\sqrt[4]{x^2}$
OR
$\sqrt[2]{x^3}$

Which of the following is correct and why?
Feb 1st 2009, 03:47 AM
earboth

Quote:

Originally Posted by mj.alawami

$\sqrt[4]{x^6}$

Attempt
$x^1\sqrt[4]{x^2}$
OR
$\sqrt[2]{x^3}$

Which of the following is correct and why?

Both!

$\sqrt[4]{x^6} = \left(x^6\right)^{\frac14} = x^{\frac64} = x^{1+\frac12} = x \cdot \sqrt{x}$

$\sqrt[4]{x^6} = \left(x^6\right)^{\frac14} = x^{\frac64} = x^{\frac32} = \sqrt{x^3}$

All times are GMT -8. The time now is 11:35 AM.

Copyright © 2005-2016 Math Help Forum. All rights reserved.