$\displaystyle \sqrt[4]{x^6}$
Attempt
$\displaystyle x^1\sqrt[4]{x^2}$
OR
$\displaystyle \sqrt[2]{x^3}$
Which of the following is correct and why?
Printable View
$\displaystyle \sqrt[4]{x^6}$
Attempt
$\displaystyle x^1\sqrt[4]{x^2}$
OR
$\displaystyle \sqrt[2]{x^3}$
Which of the following is correct and why?
Both!Quote:
Originally Posted by mj.alawami
$\displaystyle \sqrt[4]{x^6} = \left(x^6\right)^{\frac14} = x^{\frac64} = x^{1+\frac12} = x \cdot \sqrt{x} $
$\displaystyle \sqrt[4]{x^6} = \left(x^6\right)^{\frac14} = x^{\frac64} = x^{\frac32} = \sqrt{x^3} $
