1. In an arithmetic series, three consecutive terms have a sum of -9 and a product of 48. Find the possible values of these terms.
I really cant figure it out. I tries using the Sum of series formula and arithmetic series formula, but no results.
1. In an arithmetic series, three consecutive terms have a sum of -9 and a product of 48. Find the possible values of these terms.
I really cant figure it out. I tries using the Sum of series formula and arithmetic series formula, but no results.
Substituting $\displaystyle b=a+k$ and $\displaystyle c=a+2k$ in $\displaystyle a+b+c=-9$, you have :
$\displaystyle 3a+3k=-9 \Rightarrow a+k=-3$
Now substituting in $\displaystyle abc=48$, you get :
$\displaystyle a(a+k)(a+2k)=48$
We know that a+k=-3.
Hence $\displaystyle -a(a+2k)=16$ and furthermore, $\displaystyle a=-3-k$, so :
$\displaystyle -(-3-k)(-3-k+2k)=16$
$\displaystyle (3+k)(-3+k)=16$
$\displaystyle k^2-9=16$
So $\displaystyle k=\pm 5$
If $\displaystyle k=5$, then $\displaystyle a=-8$ and $\displaystyle b=\dots~,~c=\dots$
If $\displaystyle k=-5$, then ......................
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