Originally Posted by JadeKiara *Child inside me screaming (Gimme the answer please mister)* Here are my attempts too: 20d^8e^6 --------------- 2d^2e X 5d^2e^2 I don't know... Is the denominator d^43^3? no, it's $\displaystyle 10d^4e^3$ in the denominator 4 X (g^2)^2 <<< What do I do with these twos? we finished with this one, why are you going back?
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I am really very sorry. I am so tired. I have been up since 5 in the morning. So which problem is left? What was the answer to number 3?
Originally Posted by JadeKiara I am really very sorry. I am so tired. I have been up since 5 in the morning. So which problem is left? What was the answer to number 3? you already did #3, problem 5 is the only one left, the one where you asked me about the denominator. just finish that
Is it: d^8e^6 --------- 10d^4e^3 ?
No, is it: 10d^4e^3 ?
Hang on: d^14e^3 ?
Originally Posted by JadeKiara No, is it: 10d^4e^3 ? this is it, except the 10 is a 2, since 20/10 = 2 what was your other answer about?
Whew, thank goodness for that. I don't know... You can't add the 10 to the d^4?
Ha ha! So this thread ends! I finally understand now. 20 d^8 e^6 --- X ----- X ---- 10 d^4 e^2 *Laughs madly*
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