# Simplify the following indices

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• Feb 1st 2009, 01:19 AM
Jhevon
Quote:

Originally Posted by JadeKiara
*Child inside me screaming (Gimme the answer please mister)* Here are my attempts too:

20d^8e^6
---------------
2d^2e X 5d^2e^2

I don't know... Is the denominator d^43^3?

no, it's \$\displaystyle 10d^4e^3\$ in the denominator

Quote:

4 X (g^2)^2 <<< What do I do with these twos?
we finished with this one, why are you going back?
• Feb 1st 2009, 01:22 AM
JadeKiara
I am really very sorry. I am so tired. I have been up since 5 in the morning.
So which problem is left? What was the answer to number 3?
• Feb 1st 2009, 01:26 AM
Jhevon
Quote:

Originally Posted by JadeKiara
I am really very sorry. I am so tired. I have been up since 5 in the morning.
So which problem is left? What was the answer to number 3?

you already did #3, problem 5 is the only one left, the one where you asked me about the denominator. just finish that
• Feb 1st 2009, 01:29 AM
JadeKiara
Is it:

d^8e^6
---------
10d^4e^3 ?
• Feb 1st 2009, 01:30 AM
JadeKiara
No, is it:

10d^4e^3 ?
• Feb 1st 2009, 01:31 AM
JadeKiara
Hang on:

d^14e^3 ?
• Feb 1st 2009, 01:33 AM
Jhevon
Quote:

Originally Posted by JadeKiara
No, is it:

10d^4e^3 ?

this is it, except the 10 is a 2, since 20/10 = 2

what was your other answer about? :p
• Feb 1st 2009, 01:35 AM
JadeKiara
Whew, thank goodness for that. I don't know... You can't add the 10 to the d^4?

(Nod)
• Feb 1st 2009, 01:43 AM
JadeKiara
Ha ha! So this thread ends! I finally understand now.

20 d^8 e^6
--- X ----- X ----
10 d^4 e^2

*Laughs madly* (Evilgrin)
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