Simplify the following indices

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• Jan 31st 2009, 10:02 PM
I think I am getting this! But before I get excited, please check while I apply it to one of the problems:

8w^10
------
2w^4

?= 4w^6

Maybe it's not quite right, but I am on the way. Now explain where I am going wrong if you please.
• Jan 31st 2009, 10:03 PM
Jhevon
Quote:

I think I am getting this! But before I get excited, please check while I apply it to one of the problems:

8w^10
------
2w^4

?= 4w^6

Maybe it's not quite right, but I am on the way. Now explain where I am going wrong if you please.

(Clapping) that's correct (Yes)

try the others
• Jan 31st 2009, 10:09 PM
Oh, wow!!!
I will post my other answers after dinner, so I will be back on in an hour or two.

Thank you so much, you have stuck by me until I finally got what is a ridiculously easy answer to you!

See you soon!

(Hi)
• Feb 1st 2009, 12:15 AM
I have returned
Okay, I have returned...

With 2x^6 multiplied by 5x / 10x^4,
I so far have
2g^6

Is this end of simplifying? I cannot see any other ways to do so.
• Feb 1st 2009, 12:35 AM
As for:

2x^6 multiplied by 5x, divided by 10x^4
I got x^3

Is this right?

Are you still there?
• Feb 1st 2009, 12:37 AM
• Feb 1st 2009, 12:42 AM
Also, before for number 5 I need help. I meant:

20d^8e^6
---------------
2d^2e X 5d^2e^2

(Itwasntme) Anyone, please I only have half an hour. It is 8:42 here and I have until 9:15 pm. Help!!!!
• Feb 1st 2009, 12:50 AM
Jhevon
Quote:

As for:

2x^6 multiplied by 5x, divided by 10x^4
I got x^3

Is this right?

Are you still there?

that's right
• Feb 1st 2009, 12:51 AM
Jhevon
Quote:

Also, before for number 5 I need help. I meant:

20d^8e^6
---------------
2d^2e X 5d^2e^2

(Itwasntme) Anyone, please I only have half an hour. It is 8:42 here and I have until 9:15 pm. Help!!!!

you are to try this, are you not? we'll tell you if you are right or wrong
• Feb 1st 2009, 12:53 AM
Jhevon
Quote:

I so far have
2g^6

this is for which problem? the \$\displaystyle (2g^2)^2\$ problem? i already directed you with that one. please look back at post #11
• Feb 1st 2009, 12:59 AM
http://www.mathhelpforum.com/math-he...d520f892-1.gif

So... Umm...

This would then be: 2^2 X g^4 ?
• Feb 1st 2009, 01:00 AM
Jhevon
Quote:

http://www.mathhelpforum.com/math-he...d520f892-1.gif

So... Umm...

This would then be: 2^2 X g^4 ?

yes...but don't you find writing 2^2 to be awkward?
• Feb 1st 2009, 01:03 AM
Is that the end of that? Where do I go from there? I am not sure about the 2. And well yes, it is awkward, but I don't know how to do it otherwise. Remember I am new please. (Clapping)
• Feb 1st 2009, 01:07 AM
Jhevon
Quote:

Is that the end of that? Where do I go from there? I am not sure about the 2. And well yes, it is awkward, but I don't know how to do it otherwise. Remember I am new please. (Clapping)

are you not aware of what integer powers mean? 2^2 = 2*2 = 4

3^2 = 3*3 = 9

4^2 = 4*4 = 16

etc

see the pattern? the power 2 says multiply something by itself.

now try the other problems, i'm going to leave soon
• Feb 1st 2009, 01:13 AM
*Child inside me screaming (Gimme the answer please mister)* Here are my attempts too:

20d^8e^6
---------------
2d^2e X 5d^2e^2

I don't know... Is the denominator d^43^3?

4 X (g^2)^2 <<< What do I do with these twos?
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