Thread: write word problem into numerical equation and solve

I have four questions here:

1) The length of a rectangel is 3 more than twice its width. If the perimeter of the rectangle is 96 feet, find the length of the rectangle.

2) You collected $175 the second week of a charity drive. This amount was $35 more than you collected the first week. How much did you collect inthe two weeks?

3) Seven less than twice a number is the same as 9 more than 4 times the number. Find the number.

4) You have $1.80 in nickels, dimes and quarters. You have twice as many quarters as nickels. The number of dimes is one more than the number of nickels and quarters put togethers. Pick the three equations that can be made from this scenario:

a. 5N + 10D + 25Q = 180
b. 0.05N + 0.1D + 0.25 Q = 180
c. Q=2N
d. N=2Q
e. D=N + Q + 1
f. D + 1 = N + Q

Hey there!

Here's the first one:
This is a pitiful attempt at drawing a rectangle but I think you can get the gist of it, right?

Let x = the width of the rectangle

If the length is 3 more than 2 times its width then, length = 2x +3

2x + 3
_________________
|_________________| x *this is supposed to be a rectangle, i put the equation for the length above it (2x+3)


Perimeter of a rectangle = 2(length) + 2(width)

96 = 2(x) + 2(2x+3)

Solve for x. x is your width, but the question is asking for the length. You can plug your answer for x into the equation for the length and find the length.

Ok? Good luck!!

#2)

Week 1 = (week 2 - $35)
Week 2 = $175
Week 1 = $175 - $35 = $140

You can figure out the total right?

#3) Seven less than twice a number is the same as 9 more than 4 times the number. Find the number.
Let x = the unknown number

2x -7 = 4x + 9

Solve for x

4) You have $1.80 in nickels, dimes and quarters. You have twice as many quarters as nickels. The number of dimes is one more than the number of nickels and quarters put togethers. Pick the three equations that can be made from this scenario:

Let n = # of nickels, d = number of dimes, q = number of quarters

a. 5N + 10D + 25 Q = 180 **$.05 times the # of nickels, $.10 times the number of dimes, $.25 times the number of quarters

**b would be correct if 180 was written as 1.80

d. N=2Q **twice as many quarters as there are nickels

f. D + 1 = N + Q **number of dimes + one more dime is = to the total number of quarters and nickels combined

Originally Posted by cherubee

I have four questions here:

1) The length of a rectangel is 3 more than twice its width. If the perimeter of the rectangle is 96 feet, find the length of the rectangle.

L=3+2x
W=x
P=96

P=2L+2w
96=2(3+2x) + 2x
96= 6 + 4x +2x
96-6= 6x
90 = 6x
x=15

then substitute x in L,
L=3+2(15)
L= 33