Here's the question: if logbase4 (3) = p, then express logbase3 (12) in terms of p. This was a question on our exam, and I thought I got it right, but apparently I got it wrong. The answer I got was 2p. Any help would be appreciated.
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$\displaystyle \log_312=\log_3(3\cdot 4)=\log_33+\log_34=1+\frac{1}{\log_43}=1+\frac{1}{ p}$
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