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Math Help - Algebra problem with negative signs please help

  1. #1
    Newbie
    Joined
    Jan 2009
    Posts
    4

    Algebra problem with negative signs please help

    a does not = b

    a(x+b)=bx-c


    and my test review says the answer is:

    ab+c/ b-a


    but I keep getting -ab-c/a-b

    so my negative signs are the complete opposite of theirs, and I have no idea why. Am I doing it right? Is there a problem with their answer?

    here's my work :

    a(x+b)=bx-c

    ax+ab=bx-c

    ax-bx= -ab-c

    x(a-b)= -ab-c

    x= -ab-c/ a-b

    Can anyone confirm my work or show a flaw in it? Thank you so much!
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  2. #2
    Senior Member
    Joined
    Nov 2008
    Posts
    461
    Hi dude.

    Quote Originally Posted by algebra_fan View Post
    a does not = b

    a(x+b)=bx-c


    and my test review says the answer is:

    ab+c/ b-a


    but I keep getting -ab-c/a-b

    so my negative signs are the complete opposite of theirs, and I have no idea why. Am I doing it right? Is there a problem with their answer?

    here's my work :

    a(x+b)=bx-c

    ax+ab=bx-c

    ax-bx= -ab-c

    x(a-b)= -ab-c

    x= (-ab-c)/ (a-b)

    Can anyone confirm my work or show a flaw in it? Thank you so much!
    This is correct, the text book's solution is correct too,

    I think it says: x = (ab+c)/ (b-a)

    Considering your solution [ It is a-b = -(b-a) ]

    x= \frac{-ab-c}{a-b}

    = \frac{-(ab+c)}{-(b-a)} = \frac{ab+c}{b-a}

    Whatever, you did a good job!

    Regards,
    Rapha
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