Thread: Calculating the Time of a Trip

From a parking lot, you want to walk to a house on the beach. The house is located 1500 feet down a paved path. The house is 500 feet from the path.

a. Along the path, you can walk 300 feet per minute, but in the sand on the beach you can only walk 200 feet per minute.

i. How many feet per second can you walk on the path?

300 ft/min = 5 ft/s

ii. How many feet per second can you walk on the beach.

you do this one ...

Thanks! I figured it out after that. But for my next problem, I have to...

Calculate the time to the nearest second it takes to walk 1500 feet along the path and then 500 feet in the sand to the house.

Am I going to have to divide 5ft/sec to get the answer, do the same for the beach (3.3 ft/sec), and then add them?

You need to multiply how many ft/sec it takes you to walk down the path times 3 then add the ft/sec you walk on the beach and divide the whole thing by four. Remember for next time though, you need to post new problems in new threads.

Originally Posted by PhillyViDat

Thanks! I figured it out after that. But for my next problem, I have to...

Calculate the time to the nearest second it takes to walk 1500 feet along the path and then 500 feet in the sand to the house.

Am I going to have to divide 5ft/sec to get the answer, do the same for the beach (3.3 ft/sec), and then add them?

I got a bit lost in CalcQueen's explanation... So I'm going to try..

Let's list the facts:

• The path is 1500 ft. long
• You can walk this at 5 ft./sec

So.. Look at it this way: You walk 5 ft. every second. How many seconds will it take you to walk 1500 ft.? (Hint.. distance (1500 ft)/ speed (5 ft/sec) = time (x seconds))

Same thing with the other one.

You walk 3.3 ft. every second. How many seconds will it take you to walk 500 ft.? (Again.. distance (500 ft)/ speed (3.3 ft/sec) = time (x seconds))