Factorisation

**lmyeo** · January 28th 2009, 09:55 PM

3x(x-2y)2-(x-2y)3 =

**Grandad** · January 28th 2009, 10:16 PM

Hello lmyeo

Originally Posted by lmyeo

3x(x-2y)2-(x-2y)3 =

I'm guessing that your question means

$3x(x-2y)^2-(x-2y)^3$

In which case, your two main terms share a common factor of $(x-2y)^2$ . So take it out, like this:

$3x(x-2y)^2-(x-2y)^3=(x-2y)^2(3x - (x-2y))$ Can you see what I've done?

$= (x-2y)^2(3x - x+2y)$

$=(x-2y)^2(2x + 2y)$

$=2(x-2y)^2(x + y)$

Grandad

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