Tricky solution set.
The solution set for the equation: x - 4 - square root of(9x) = 0 consists of:
A) exactly one negative number
B) exactly one positive number ---Answer
C) exactly on positive number and one negative number.
D) exactly two negative numbers.
E) exactly two positive.
B) is the answer, but I have no idea why and neither does my dad, can someone please help me with this? (Headbang)
are you sure?
Are you positive that there is only one positive answer? because I got two positive answers. x=16 and x=1
It says that question 25.'s (this question) answer is B.
So I'm pretty sure... but could you show me what you did? Because I didn't even get that close to an answer.
Thanks for the speedy reply.
Edit: Nevermind I get what you did! 1 doesn't work because 1-4-3= -6 not 0
so can you show me how you got 16 ?
x - 4 - sqrt(9x) = 0 add sqrt(9x) to both sides
x - 4 = sqrt(9x) now square both sides
x^2 - 8x + 16 = 9x subtract 9x from both sides
x^2 - 17x + 16 = 0 factor the left hand side
(x - 16) (x - 1) = 0 set both values equal to 0
x = 16 x = 1
I didn't even remember to check the answers. good job, there's your answer. 16 works, but not 1
I forgot one of the most basic things in Algebra, gosh I feel dumb.
Thank you!! :)