solve the equation by introducing a substitution that transforms the equation to quadratic form........ x^2/3 + 4x^1/3 = 0
Hello, Jshizza1228!
Solve the equation by introducing a substitution that transforms
the equation to quadratic form: .$\displaystyle x^{\frac{2}{3}}+ 4x^{\frac{1}{3}} \:= \:0$
We have: .$\displaystyle \left(x^{\frac{1}{3}}\right)^2 + 4\left(x^{\frac{1}{3}}\right) \:=\:0$
Let $\displaystyle z \:=\:x^{\frac{1}{3}}$
. . and we have: .$\displaystyle z^2 + 4z \:=\:0$
Got it?