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Math Help - algebra equation

  1. #1
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    algebra equation

    solve the equation by introducing a substitution that transforms the equation to quadratic form........ x^2/3 + 4x^1/3 = 0
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  2. #2
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    Quote Originally Posted by Jshizza1228 View Post
    solve the equation by introducing a substitution that transforms the equation to quadratic form........ x^2/3 + 4x^1/3 = 0
    Substitute u = x^{1/3}.
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  3. #3
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    Hello, Jshizza1228!

    Solve the equation by introducing a substitution that transforms
    the equation to quadratic form: . x^{\frac{2}{3}}+ 4x^{\frac{1}{3}} \:= \:0

    We have: . \left(x^{\frac{1}{3}}\right)^2 + 4\left(x^{\frac{1}{3}}\right) \:=\:0


    Let z \:=\:x^{\frac{1}{3}}

    . . and we have: . z^2 + 4z \:=\:0


    Got it?

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