Results 1 to 2 of 2

Math Help - Surds

  1. #1
    Newbie
    Joined
    Jan 2009
    Posts
    1

    Surds

    (square root)6(4(square root)2 + 3(square root)3) - 38 / 5(square root)2 - 2 (square root)3

    *the square root's number is the one to the right, not to the left*

    I apologize for not having the stuff to make the square root signs and etc.

    But can anyone teach me how to solve this equation, do I try to change (square root)6 to 6 by mulitplying it to the whole equation, multiply it into (4(square root)2 + 3(square root)3) or change 4(square root)2 into (square root)32 and then multiply it (square root)6 into (square root)32 and try to factorize it down again? Or any other ways you can tell me about?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Nov 2008
    Posts
    47
    Is 5(square root)2 - 2 (square root)3 the ONE denominator? Or 2 (square root)3 is subtracted from fraction 38/ 2 (square root)3? Is it 38/[5(square root)2 - 2 (square root)3]?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Help with Surds
    Posted in the Algebra Forum
    Replies: 8
    Last Post: January 5th 2012, 04:08 PM
  2. Something to do with surds?
    Posted in the Algebra Forum
    Replies: 4
    Last Post: July 11th 2011, 11:33 AM
  3. surds
    Posted in the LaTeX Help Forum
    Replies: 3
    Last Post: June 4th 2009, 05:55 PM
  4. surds
    Posted in the Algebra Forum
    Replies: 2
    Last Post: June 4th 2009, 01:30 AM
  5. surds
    Posted in the Algebra Forum
    Replies: 1
    Last Post: May 29th 2009, 05:40 AM

Search Tags


/mathhelpforum @mathhelpforum