1) From the first equation
Replacing y in the second equation we have
This equation has:
a) a unique solution if
b) infinetely many solutions if
c) no solution if
hello all, frantic rush to get all the h/w done before school starts again lol.
here it is i have absolutely no idea what i am suppose to do here, the book provides little to no help at all.
This is the example they give which i need help figuring out as well as the actual problem.
Consider the simultaneous linear equations
(m-2)x + y = 2 and mx+2y = k
Find the values of m and k such that the system of equations has
a) a unique solution
b) no solution
c) infinitely many solutions
Now for the question......
Find the value of m for which the simultaneous equations
(m+3)x +my = 12
(m-1)x + (m-3)y = 7
have no solution.
i no that when they want the equations to have no solutions it means the lines are parallel and when the infinite solutions they are the same line however i have no idea what to do about it.
Thanks
Josh
It should be clear where has come from.
a) It should be clear that from the solution red_dog gives here that you can solve for a unique value of x (and hence y) eg. m = 2 and k = anything (3, say).
b) What happens when you substitute the solution red_dog gives here ....? Can you get a unique value of x or can x be any value ....?
c) What happens if m = 4 and k = 2, say ....?