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Math Help - Logs

  1. #1
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    Jan 2009
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    Question Logs

    i have two questions.

    so one problem is:
    2log(3x)-log(x)=2

    i don't remember if you apply the 2 to the (3x) or if it's like algebra and you just divide it by 2 to cancel out. oh and then you'd divide log 3x by log x right to combine them because they have the same base?


    the other one is:
    15log base 1/3(1/27) + logbase 1/4(256)= u

    so does the 15 go to the 1/3 or 1/27 or do you just divide it.
    and you can't combine them because they have different bases right?

    sorry if this is confusing..
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  2. #2
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    Dec 2008
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    Quote Originally Posted by lonejunior View Post
    i have two questions.

    so one problem is:
    2log(3x)-log(x)=2

    i don't remember if you apply the 2 to the (3x) or if it's like algebra and you just divide it by 2 to cancel out. oh and then you'd divide log 3x by log x right to combine them because they have the same base?


    the other one is:
    15log base 1/3(1/27) + logbase 1/4(256)= u

    so does the 15 go to the 1/3 or 1/27 or do you just divide it.
    and you can't combine them because they have different bases right?

    sorry if this is confusing..
    1)

    2 log(3x) - log x = 2
    2 (log 3 + log x ) - log x = 2

    can you do it from here?

    2)
    example
    <br />
log_{10}1000 = 3<br />
    thats because 10^3 = 1000
    can you work out your second equation now?
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  3. #3
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    Jan 2009
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    thanks for the help.
    i understand what you meant for the first problem and i was able to solve it
    and i understand the example you gave me, but i don't understand how it relates to the problem
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  4. #4
    Member
    Joined
    Dec 2008
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    152
    <br />
log_{(\frac{1}{3})}\frac{1}{27} = 3 <br />

    <br />
log_{(\frac{1}{4})}256 = -4<br />
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