How many gallons of a 51% alcohol solution should be added to a 57% alcohol solution to make 438 gallons of a 55% solution?
Let be the amount (in gallons) of the weaker (51%) solution in the final product and let be the amount (in gallons) of the stronger solution.
Now we know that we want the final amount to be 438 gallons, so
. We also know that we want the final product to be 438 gallons of 55% alcohol, so .
You then have a system of linear equations in two variables. The easiest way to solve this is probably to solve the first equation for , then substitute that into the second equation and solve for :
Then you just add 57% solution until you have 438 gallons.
You want gallons to make up 8% of the new solution, so divide by 0.08, giving total gallons of solution. Then subtract the amount of original soap solution, and .
Therefore, if the amount of the original soap solution was gallons, you'd have to add gallons of pure water to make an 8% solution.
For example, if you had 100 gallons of soap solution to start, you'd add 150 gallons of pure water.
(MKN, welcome to the forum. In the future, you should post questions like this to a new thread rather than replying to an old one. Good luck with the soap solution! )