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Originally Posted by tmac11522 what have you done so far?
i multiplied both sides of the equation by (2x+5)(x+4), simplified and got it down to 0=3x^2+10x+35 and i'm stuck
Originally Posted by tmac11522 i multiplied both sides of the equation by (2x+5)(x+4), simplified and got it down to 0=3x^2+10x+35 and i'm stuck now use quadratic formula....
Originally Posted by tmac11522 i multiplied both sides of the equation by (2x+5)(x+4), simplified and got it down to 0=3x^2+10x+35 and i'm stuck Recall that a quadratic of the form: $\displaystyle ax^2 + bx + c = 0$ Can be solved by using this equation: $\displaystyle x = \frac{-b \pm \sqrt {b^2 - 4ac}}{2a}$
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