Many thanks to anyone who can help solve this little bugger
Rearrange for x, so x=?
x/(x-a)=(x-b)/(x-c)
Workings and an explanation would be handy if available
381
the question is written:
Reaarange the subject of the following,
x/(x-a)=(x-b)/(x-c) Rearrange for "x"
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A similar question would be: Rearrange for "s"
a=ut+0.5st^2 original arrangment
a-ut=0.5st^2 minus "ut" from each side
(a-ut)/t^2=0.5s divide each side by "t^2"
2((a-ut)/t^2)=s divide by "0.5" so multiply by 2
^ represents a power so 2^2 = 2 squared
Hope this helps.
Thanks, 381