Results 1 to 5 of 5

Math Help - rearranging for x

  1. #1
    Banned
    Joined
    Jan 2009
    Posts
    8

    rearranging for x

    Many thanks to anyone who can help solve this little bugger

    Rearrange for x, so x=?

    x/(x-a)=(x-b)/(x-c)

    Workings and an explanation would be handy if available

    381
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member topher0805's Avatar
    Joined
    Jan 2008
    From
    Vancouver
    Posts
    336
    Quote Originally Posted by tomh381 View Post
    Many thanks to anyone who can help solve this little bugger

    Rearrange for x, so x=?

    x/(x-a)=(x-b)/(x-c)

    Workings and an explanation would be handy if available

    381
    The answer is 381? You must be withholding some information from us.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor
    Jester's Avatar
    Joined
    Dec 2008
    From
    Conway AR
    Posts
    2,338
    Thanks
    19
    Quote Originally Posted by tomh381 View Post
    Many thanks to anyone who can help solve this little bugger

    Rearrange for x, so x=?

    x/(x-a)=(x-b)/(x-c)

    Workings and an explanation would be handy if available

    381
    Cross multiply

    x(x-c) = (x-b)(x-a)

    then expand

    x^2 - cx = x^2 - (a+b)x + ab

    cancel and move all x terms to the left

    (a+b-c)x = ab

    then isolate x

    x = \frac{ ab}{a+b-c}
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Banned
    Joined
    Jan 2009
    Posts
    8
    the question is written:

    Reaarange the subject of the following,

    x/(x-a)=(x-b)/(x-c) Rearrange for "x"

    ----------------------------------------------------------------------------
    A similar question would be: Rearrange for "s"

    a=ut+0.5st^2 original arrangment

    a-ut=0.5st^2 minus "ut" from each side

    (a-ut)/t^2=0.5s divide each side by "t^2"

    2((a-ut)/t^2)=s divide by "0.5" so multiply by 2

    ^ represents a power so 2^2 = 2 squared

    Hope this helps.

    Thanks, 381
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by tomh381 View Post
    Many thanks to anyone who can help solve this little bugger

    Rearrange for x, so x=?

    x/(x-a)=(x-b)/(x-c)

    Workings and an explanation would be handy if available

    381
    Thread closed. Pre-emptive action due to questions in other threads getting deleted.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. help rearranging this
    Posted in the Algebra Forum
    Replies: 6
    Last Post: October 31st 2010, 11:22 AM
  2. Rearranging help?
    Posted in the Algebra Forum
    Replies: 2
    Last Post: September 30th 2010, 01:59 PM
  3. Rearranging
    Posted in the Algebra Forum
    Replies: 9
    Last Post: July 17th 2008, 12:24 AM
  4. Rearranging
    Posted in the Math Topics Forum
    Replies: 2
    Last Post: June 15th 2008, 11:17 AM
  5. rearranging
    Posted in the Algebra Forum
    Replies: 2
    Last Post: December 17th 2007, 08:51 AM

Search Tags


/mathhelpforum @mathhelpforum