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Math Help - Simplyify using the law of exponents

  1. #1
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    Simplyify using the law of exponents

    simplify the following :-

    (10ˆ1-n)ˆn
    10000nˆ2+2
    ____________ *
    ___________
    (1000ˆn)ˆn+1
    100ˆ3-n

    Please answer the following in steps because i dont even know how to answer this question
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  2. #2
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    is there a typo?

    (10^1-n)^n or  (10^{1-n})^n?
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  3. #3
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    Quote Originally Posted by metlx View Post
    is there a typo?

    (10^1-n)^n or  (10^{1-n})^n?
    Is the answer nˆ2 +3
    Thank you for your help but i can't understand what you wrote please write in more step
    Thank you
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  4. #4
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    Quote Originally Posted by mj.alawami View Post
    simplify the following :-




    (101-n)n
    10000n2+2






    ____________ *
    ___________






    (1000n)n+1
    1003-n




    Please answer the following in steps because i dont even know how to answer this question
    Hi mj,

    You're going to have to be clearer with your expressions. Use parentheses to separate things. Is this what you are trying to say:

    \frac{(10^{1-n})^n}{(1000^n)^{n+1}}\cdot \frac{10000^{n^2+2}}{100^{3-n}}
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  5. #5
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    Quote Originally Posted by masters View Post
    Hi mj,

    You're going to have to be clearer with your expressions. Use parentheses to separate things. Is this what you are trying to say:

    \frac{(10^{1-n})^n}{(1000^n)^{n+1}}\cdot \frac{10000^{n^2+2}}{100^{3-n}}
    Yes your equation is correct,please answer it becuase i don't know how to do it

    btw thank you very much for taking the time to help me ,I really appreciate it
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  6. #6
    A riddle wrapped in an enigma
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    Hi mj,


    \frac{(10^{1-n})^n}{(1000^n)^{n+1}}\cdot \frac{10000^{n^2+2}}{100^{3-n}}=\frac{10^{n(1-n)}}{10^{3n(n+1)}} \cdot \frac{10^{4(n^2+2)}}{10^{2(3-n)}}=\frac{10^{n-n^2}}{10^{3n^2+3n}} \cdot \frac{10^{4n^2+8}}{10^{6-2n}}=

    Can you finish up?
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