Can someone help me with this one?
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(4x-22)(2x+4)-5(x+2)(x-4) = 0
8x^2+16x-44x-88-5(x^2-4x+2x-8) = 0
8x^2+16x-44x-88-5x^2+10x+40 = 0
3x^2-18x-48 = 0
(x-8)(3x+6) = 0
x=8 or x = -2
Hope it helps. Originally Posted by hkerbest Can someone help me with this one?
Last edited by tester85; January 26th 2009 at 06:03 AM.
Originally Posted by hkerbest Can someone help me with this one? first get the lcd that is
Originally Posted by princess_21 first get the lcd that is Sorry i don't think this is right. As the answer you got is x = 8/5, when you resubstitute it back to the solution. You will not get back zero. I will format my previous solution using latex shortly.
right, oops my mistake..
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