Hey guys, having a little trouple with functions. Heres the problems:

1) 4^x+2-4^x=15

2)7^x^2=10

3) 2^x=3^x

and i have no idea how to post other q's with my keyboard(Headbang)

thanx for the help though everyone(Happy)

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- Jan 25th 2009, 11:19 PMBaginomanLogarithmic Functions....help =)
Hey guys, having a little trouple with functions. Heres the problems:

1) 4^x+2-4^x=15

2)7^x^2=10

3) 2^x=3^x

and i have no idea how to post other q's with my keyboard(Headbang)

thanx for the help though everyone(Happy) - Jan 25th 2009, 11:59 PMearboth
- Jan 26th 2009, 04:17 PMBaginoman
awesome, those confused me lol

how about:

1) log3^x=log3(1/x)+4 (keep in mind both 3's are log of 3)

2) log(7y + 1)= 2 log(y + 3) - log 2

3) log(3x - 4)/log x =2

thank you again guys - Jan 26th 2009, 05:24 PMbecker89
second question: just use logarithm rules,

the 2 goes back to the exponent,then you have a difference of logarithms

third question: change of bases rule - Jan 26th 2009, 08:39 PMearboth
1. Do us and do yourself a favour and start a new thread if you have new questions. Otherwise you risk that nobody will notice your need for help.

2. I don't understand the equation in 1). Do you mean:

or or ...

3. If you have some difficulties to use becker89 hint, here is a starter:

Now de-logarithmize. You'll get a quadratic equation in y. My result is: y = 7 or y = 1

4. Multiply the equation through by log(x):

De-logarithmize and solve the quadratic equation. This equation doesn't have a real solution. - Jan 26th 2009, 08:54 PMBaginoman
- Jan 26th 2009, 09:13 PMearboth
- Jan 26th 2009, 09:20 PMBaginoman
- Jan 26th 2009, 10:30 PMearboth
- Jan 26th 2009, 10:38 PMBaginoman
- Jan 26th 2009, 10:49 PMearboth