14 + .80x =46
14 -14 +.80x =46 -14
.80x= 32
.80 80 or.80x/.80 32/.80 the answer is 40, but how exactly does .80x/.80 32/.80 = 40 meaning the mechanics of
I know x equals 40, but what i want to know is how to single out the x to the left to get 40
14 + .80x =46
14 -14 +.80x =46 -14
.80x= 32
.80 80 or.80x/.80 32/.80 the answer is 40, but how exactly does .80x/.80 32/.80 = 40 meaning the mechanics of
I know x equals 40, but what i want to know is how to single out the x to the left to get 40
there is a rule for it.
$\displaystyle
\frac {x}{\frac{y}{z}} = \frac { x\cdot z}{y}
$
or more common example
$\displaystyle
\frac{100}{\frac{20}{2}} = \frac {100}{10} = 10 = \frac{100 \cdot 2}{20}
$
OR
$\displaystyle
\frac{4}{2}=\frac{\frac{4}{1}}{\frac{2}{1}} = \frac {4\cdot1}{2\cdot1}
$
When you have a fraction in the denominator of a fraction:
$\displaystyle \frac{32}{\frac{4}{5}}$
you can multiply the top of the fraction by the reciprocal of the bottom fraction:
Think of 32 being the same thing as $\displaystyle \frac{32}{1}$
So,
$\displaystyle \frac{\frac{32}{1}}{\frac{4}{5}}$
= $\displaystyle \frac{32}{1}\cdot\frac{5}{4}$
Then just multiply across each fraction:
$\displaystyle \frac{160}{4} = 40$