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Math Help - Rationalizing denominators

  1. #1
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    Rationalizing denominators

    \frac{5 \sqrt{2}}{3 \sqrt{7x}}
    Last edited by mr fantastic; January 24th 2009 at 06:24 PM. Reason: Fixed the latex
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by hershey93 View Post
    \frac{5 \sqrt{2}}{3 \sqrt{7x}}
    You need to multiply by "1", which in our case would be \frac{\sqrt{7x}}{\sqrt{7x}}

    So, you would have \frac{5\sqrt{2}}{3\sqrt{7x}}\cdot\frac{\sqrt{7x}}{  \sqrt{7x}}=\frac{5\sqrt{2}\cdot\sqrt{7x}}{3\left(\  sqrt{7x}\right)^2}=\frac{5\sqrt{14x}}{3\cdot 7x}=\color{red}\boxed{\frac{5\sqrt{14x}}{21x}}

    Does this make sense?
    Last edited by mr fantastic; January 24th 2009 at 06:29 PM. Reason: Edited in context of irrelevant posts that were deleted once the OP's latex was fixed.
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  3. #3
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    Quote Originally Posted by Chris L T521 View Post
    You need to multiply by "1", which in our case would be \frac{\sqrt{7x}}{\sqrt{7x}}

    So, you would have \frac{5\sqrt{2}}{3\sqrt{7x}}\cdot\frac{\sqrt{7x}}{  \sqrt{7x}}=\frac{5\sqrt{2}\cdot\sqrt{7x}}{3\left(\  sqrt{7x}\right)^2}=\frac{5\sqrt{14x}}{3\cdot 7x}=\color{red}\boxed{\frac{5\sqrt{14x}}{21x}}

    Does this make sense?
    Ya that seems right...that was exactly what i thought it would look like.
    Thanx for your help Chris..Have a good night
    Last edited by mr fantastic; January 24th 2009 at 06:29 PM. Reason: See above reason
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