I'm reviewing for a math exam and i need help finding zeros again. =(
How many zeros do the following functions have?
a) y= 6x^2 -6x -9
b) f(x)= -6(x+3)^2 -2
For zeros, you set the function equal to 0.
$\displaystyle 6x^2-6x-9 = 0 $
You can solve this using the quadratic equation:
$\displaystyle x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} $
$\displaystyle -6(x+3)^2 - 2 = 0 $
$\displaystyle -6(x^2+6x+9) - 2 = 0 $
$\displaystyle -6x^2-36x-56 = 0 $
Use the same formula.