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Math Help - solving exponents

  1. #1
    Junior Member
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    solving exponents

    I have been working on this problem for a week now and I cant solve it and Im sure its easy.
    The expression e^(x-8)/e^(x-2) can be written as e^f(x), where f(x) is a function of x. Find f(x).
    I tried using laws of exponents and converting it to e^(x-8)*e^(-x+2) to get e^(-6) which is still wrong. Thanks to anyone who can help.
    AC
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  2. #2
    Super Member
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    Quote Originally Posted by Casas4 View Post
    I have been working on this problem for a week now and I cant solve it and Im sure its easy.
    The expression e^(x-8)/e^(x-2) can be written as e^f(x), where f(x) is a function of x. Find f(x).
    I tried using laws of exponents and converting it to e^(x-8)*e^(-x+2) to get e^(-6) which is still wrong. Thanks to anyone who can help.
    AC
     \frac{e^{(x-8)}}{e^{(x-2)}} = e^{(x-8)}\times (e^{(x-2)})^{-1}

      = e^{(x-8)}\times e^{(2-x)}

      = e^{(x-8) + (2-x)}

      = e^{x-8 + 2-x}

      = e^{-6}

    You are correct.
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